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function [test_targets, best_fun] = genetic_programming(train_patterns, train_targets, test_patterns, params) % A genetic programming algorithm for classification % % train_patterns - Train patterns % train_targets - Train targets % test_patterns - Test patterns % params - [Initial function length, Number of generations, Number of solutions] % %Outputs % test_targets - Predicted targets % func - The best solution found IterDisp = 10; [Ni, M] = size(train_patterns); x = train_patterns; Uc = unique(train_targets); %Find parameters [Flength, Ngenerations, Nsol] = process_params(params); if (Flength) > 20, warning('This may take some time!') end %Define basic operators. If division by zero is unwanted, remove the devision operator warning off %To suppress all those divide by zero warnings operators = [' +'; ' -'; '.*'; './']; base = size(operators,1); for i = 1:Ni, operators(base+i,:) = ['X' num2str(i)]; end %Define the basic tree shape leafs = []; solutions = zeros(1,Nsol); %Pointer to the first leaf in the solution for i = 1:Nsol; solutions(i) = length(leafs) + 1; leafs = foliage(leafs, operators, Flength); end disp(['Starting with ' num2str(Nsol) ' solutions, totaling ' num2str(length(leafs)) ' leaves.']) best = 0; %Start doing the mutations for i = 1:Ngenerations, %Rank each solution ranking = zeros(1,Nsol); for j = 1:Nsol, func = collect_tree(solutions(j), leafs); for k = 1:Ni, func = strrep(func, ['X' num2str(k)], ['x(' num2str(k) ',:)']); end %Check if this string is a valid solution, and if so, put the ranking into place try t = eval(func); if (length(Uc) == 2) t = t > 0; else t = round(t); end ranking(j) = sum(t == train_targets) / length(train_targets); catch end end %Display if (i/IterDisp == floor(i/IterDisp)), disp(['Iteration ' num2str(i) ': Best solution has ' num2str(max(ranking)*100) '% correct (The best so far was ' num2str(best*100) '% correct).']) end %Sort the solutions according to rank [m, indices] = sort(ranking); indices = fliplr(indices); %It is sometimes good to save the best solution so far, in case the mutations ruin it! if (max(ranking) > best), best = max(ranking); best_fun = collect_tree(solutions(indices(1)), leafs); end %Start the genetic operations for j = 1:floor(Nsol/2), %Select two solutions according to their rank s1 = indices(j*2-1); s2 = indices(j*2); %Now do the genetic operators %There is no insertion in this implementation, as it generates too many impossible solutions k = 1 + floor(3*rand(1)); switch k, case 1, %Replications %Replicate from 2 to 1 or vice versa? if rand(1) > .5, temp = s1; s1 = s2; s2 = temp; end %Find where from to replicate node_number1 = walk_along(solutions(s1), leafs); node_number2 = walk_along(solutions(s2), leafs); [new_node, leafs] = copy(node_number1, leafs); %Put on left or right? if rand(1) > .5, %Put on left leafs(node_number2).left = new_node; else leafs(node_number2).right = new_node; end case 2, %Crossover %First, decide where to do the crossover node_number1 = walk_along(solutions(s1), leafs); node_number2 = walk_along(solutions(s2), leafs); %Change pointers by finding which leaf points to each of the leafs to change l1 = []; l2 = []; r1 = []; r2 = []; for m = 1:length(leafs), if ~isempty(leafs(m).left), if leafs(m).left == node_number1, l1 = m; end if leafs(m).left == node_number2, l2 = m; end end if ~isempty(leafs(m).right), if leafs(m).right == node_number1, r1 = m; end if leafs(m).right == node_number2, r2 = m; end end end if ~isempty([l1 r1]) & ~isempty([l2 r2]), if isempty(l1), %It is on the right of 1 if isempty(l2), leafs(r2).right = node_number1; leafs(r1).right = node_number2; else leafs(l2).left = node_number1; leafs(r1).right = node_number2; end else if isempty(l2), leafs(r2).right = node_number1; leafs(l1).right = node_number2; else leafs(l2).left = node_number1; leafs(l1).right = node_number2; end end end case 3, %Mutation %Mutate s1 or s2? if rand(1) > .5, temp = s1; s1 = s2; s2 = temp; end %First, decide where to do the mutation node_number1 = walk_along(solutions(s1), leafs); %Choose the new operator o1 = 1 + floor(rand(1)*size(operators,1)); %Mutate! leafs(node_number1).operator = operators(o1,:); if strcmp(operators(o1,1),'X'), leafs(node_number1).left = []; leafs(node_number1).right = []; end end end end %Classify test patterns disp(['Will use a solution with ' num2str(best*100) '% correct for the test patterns']) dfun = best_fun; for k = 1:Ni, dfun = strrep(dfun, ['X' num2str(k)], ['test_patterns(' num2str(k) ',:)']); end test_targets = eval(dfun); if (length(Uc) == 2) test_targets = test_targets > 0; end %END function [root, leafs] = copy(start_point, leafs) %Make a copy of a branch, from the start point until its end. Return a pointer to the copy N = length(leafs) + 1; leafs(N).operator = leafs(start_point).operator; if ~isempty(leafs(start_point).left), [root, leafs] = copy(leafs(start_point).left, leafs); leafs(N).left = root; end if ~isempty(leafs(start_point).right), [root, leafs] = copy(leafs(start_point).right, leafs); leafs(N).right = root; end root = N; %END function node = walk_along(start_point, leafs); %Find where to mutate a solution along a tree. This is recursive r = 1 + floor(rand(1)*4); switch r, case {1,2}, %Go no further node = start_point; case 3, %If possible, go right if ~isempty(leafs(start_point).right), node = walk_along(leafs(start_point).right, leafs); else node = start_point; end case 4, %If possible, go left if ~isempty(leafs(start_point).left), node = walk_along(leafs(start_point).left, leafs); else node = start_point; end end %END function s = collect_tree(pointer, leafs) %Find the tree function recursively if ~isempty(leafs(pointer).left), s = ['(' collect_tree(leafs(pointer).left, leafs) ')']; else s = []; end s = [s leafs(pointer).operator]; if ~isempty(leafs(pointer).right), s = [s '(' collect_tree(leafs(pointer).right, leafs) ')']; end %END function [leafs, N] = foliage(leafs, operators, remaining_depth) %Recursively add leafs in order to build the initial tree N = length(leafs)+1; if (remaining_depth > 0), r = floor(rand(1)*size(operators,1)) + 1; leafs(N).operator = operators(r,:); if ~strcmp(leafs(N).operator(1), 'X'), %The operator is numeric, so more leafs are needed [leafs, added] = foliage(leafs, operators, remaining_depth-1); leafs(N).left = added; [leafs, added] = foliage(leafs, operators, remaining_depth-1); leafs(N).right = added; else leafs(N).left = []; leafs(N).right = []; end else in = find(operators(:,1) == 'X'); r = floor(rand(1)*length(in)) + 1; leafs(N).operator = ['X' num2str(r)]; leafs(N).left = []; leafs(N).right = []; end