www.gusucode.com > 基于lingo求所以解,对潮流计算求出所有解 > matpower4.1/t/t_case9_opf.m
function [baseMVA, bus, gen, branch, areas, gencost] = t_case9_opf %T_CASE9_OPF Power flow data for 9 bus, 3 generator case, with OPF data. % Please see CASEFORMAT for details on the case file format. % MATPOWER % $Id: t_case9_opf.m,v 1.10 2010/11/09 16:44:46 cvs Exp $ %% MATPOWER Case Format : Version 1 %%----- Power Flow Data -----%% %% system MVA base baseMVA = 100; %% bus data % bus_i type Pd Qd Gs Bs area Vm Va baseKV zone Vmax Vmin bus = [ 1 3 0 0 0 0 1 1 0 345 1 1.1 0.9; 2 2 0 0 0 0 1 1 0 345 1 1.1 0.9; 30 2 0 0 0 0 1 1 0 345 1 1.1 0.9; 4 1 0 0 0 0 1 1 0 345 1 1.1 0.9; 5 1 90 30 0 0 1 1 0 345 1 1.1 0.9; 6 1 0 0 0 0 1 1 0 345 1 1.1 0.9; 7 1 100 35 0 0 1 1 0 345 1 1.1 0.9; 8 1 0 0 0 0 1 1 0 345 1 1.1 0.9; 9 1 125 50 0 0 1 1 0 345 1 1.1 0.9; ]; %% generator data % bus Pg Qg Qmax Qmin Vg mBase status Pmax Pmin gen = [ 1 0 0 300 -300 1 100 1 250 90; 2 163 0 300 -300 1 100 1 300 10; 30 85 0 300 -300 1 100 1 270 10; ]; %% branch data % fbus tbus r x b rateA rateB rateC ratio angle status branch = [ 1 4 0 0.0576 0 0 250 250 0 0 1; 4 5 0.017 0.092 0.158 0 250 250 0 0 1; 5 6 0.039 0.17 0.358 150 150 150 0 0 1; 30 6 0 0.0586 0 0 300 300 0 0 1; 6 7 0.0119 0.1008 0.209 40 150 150 0 0 1; 7 8 0.0085 0.072 0.149 250 250 250 0 0 1; 8 2 0 0.0625 0 250 250 250 0 0 1; 8 9 0.032 0.161 0.306 250 250 250 0 0 1; 9 4 0.01 0.085 0.176 250 250 250 0 0 1; ]; %%----- OPF Data -----%% %% area data % area refbus areas = [ 1 5; ]; %% generator cost data % 1 startup shutdown n x1 y1 ... xn yn % 2 startup shutdown n c(n-1) ... c0 gencost = [ 1 0 0 4 0 0 100 2500 200 5500 250 7250; 2 0 0 2 24.035 -403.5 0 0 0 0 0 0; 1 0 0 3 0 0 200 3000 300 5000 0 0; ];